Найду корень уравнения: 2cos(x/3)=√3
Разделим обе части ур-ния на 2
pi x1 = -- 2
11*pi x2 = ----- 2
сумма
pi 11*pi 0 + -- + ----- 2 2
=
6*pi
произведение
pi 11*pi 1*--*----- 2 2
=
2 11*pi ------ 4
x1 = 39.2699081698724
x2 = 54.9778714378214
x3 = -1471.83615820682
x4 = 95.8185759344887
x5 = 73.8274273593601
x6 = 76.9690200129499
x7 = 1.5707963267949
x8 = 64595.8573467865
x9 = -54.9778714378214
x10 = -20.4203522483337
x11 = -73.8274273593601
x12 = -4069.93328272558
x13 = -92.6769832808989
x14 = 58.1194640914112
x15 = 12288.3396645165
x16 = -76.9690200129499
x17 = 17.2787595947439
x18 = 3278.25193402095
x19 = 19228.1178362963
x20 = -58.1194640914112
x21 = -962.898148325272
x22 = -39.2699081698724
x23 = -17.2787595947439
x24 = 92.6769832808989
x25 = -95.8185759344887
x26 = 36.1283155162826
x27 = 130.376095123976
x28 = 20.4203522483337
x29 = -36.1283155162826
x30 = 12589.9325592611
x31 = -1.5707963267949