Найду корень уравнения: 2sin(x/2)=√3
Разделим обе части ур-ния на 2
2*pi x1 = ---- 3
4*pi x2 = ---- 3
сумма
2*pi 4*pi 0 + ---- + ---- 3 3
=
2*pi
произведение
2*pi 4*pi 1*----*---- 3 3
=
2 8*pi ----- 9
x1 = -20.943951023932
x2 = 39.7935069454707
x3 = 64.9262481741891
x4 = -73.3038285837618
x5 = -46.0766922526503
x6 = -33.5103216382911
x7 = 67.0206432765823
x8 = 1336.22407532686
x9 = 52.3598775598299
x10 = -83.7758040957278
x11 = -23.0383461263252
x12 = -96.342174710087
x13 = 16.7551608191456
x14 = 14.6607657167524
x15 = 29.3215314335047
x16 = 54.4542726622231
x17 = 41.8879020478639
x18 = 27.2271363311115
x19 = 77.4926187885482
x20 = 92.1533845053006
x21 = -35.6047167406843
x22 = -10.471975511966
x23 = -123.569311041199
x24 = 8321.03174180816
x25 = -8.37758040957278
x26 = 79.5870138909414
x27 = 6750.23541501327
x28 = -71.2094334813686
x29 = -58.6430628670095
x30 = 4.18879020478639
x31 = 102.625360017267
x32 = 90.0589894029074
x33 = 2.0943951023932
x34 = -60.7374579694027
x35 = -85.870199198121
x36 = -98.4365698124802
x37 = -48.1710873550435