Найду корень уравнения: 2х²-3х-2=0
2 2*x - 3*x - 2 = 0
a*x^2 + b*x + c = 0
D = b^2 - 4 * a * c =
(-3)^2 - 4 * (2) * (-2) = 25
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
x1 = -1/2
x2 = 2
x1 = 2.0
x2 = -0.5