Найду корень уравнения: cos(3x/7)=0
с изменением знака при 0
7*pi x1 = ---- 6
7*pi x2 = ---- 2
сумма
7*pi 7*pi 0 + ---- + ---- 6 2
=
14*pi ----- 3
произведение
7*pi 7*pi 1*----*---- 6 2
=
2 49*pi ------ 12
x1 = -76.9690200129499
x2 = 40.317105721069
x3 = -10.9955742875643
x4 = 62.3082542961976
x5 = 32.9867228626928
x6 = -40.317105721069
x7 = -69.6386371545737
x8 = 91.6297857297023
x9 = -3.66519142918809
x10 = 76.9690200129499
x11 = 18.3259571459405
x12 = 3.66519142918809
x13 = -32.9867228626928
x14 = -98.9601685880785
x15 = 84.2994028713261
x16 = -18.3259571459405
x17 = -8265.00667281915
x18 = -91.6297857297023
x19 = 54.9778714378214
x20 = -62.3082542961976
x21 = 98.9601685880785
x22 = -25.6563400043166
x23 = 25.6563400043166
x24 = 2070.83315749127
x25 = 69.6386371545737
x26 = -54.9778714378214
x27 = 10.9955742875643
x28 = 47.6474885794452
x29 = -84.2994028713261
x30 = 172.26399717184
x31 = -47.6474885794452
x32 = -106.290551446455