64^x=8 (уравнение) Учитель очень удивится увидев твоё верное решение 😼
Найду корень уравнения: 64^x=8
Решение
Подробное решение
Дано уравнение:6 4 x = 8 64^{x} = 8 6 4 x = 8 или6 4 x − 8 = 0 64^{x} - 8 = 0 6 4 x − 8 = 0 или6 4 x = 8 64^{x} = 8 6 4 x = 8 или6 4 x = 8 64^{x} = 8 6 4 x = 8 - это простейшее показательное ур-ние Сделаем заменуv = 6 4 x v = 64^{x} v = 6 4 x получимv − 8 = 0 v - 8 = 0 v − 8 = 0 илиv − 8 = 0 v - 8 = 0 v − 8 = 0 Переносим свободные слагаемые (без v) из левой части в правую, получим:v = 8 v = 8 v = 8 Получим ответ: v = 8 делаем обратную замену6 4 x = v 64^{x} = v 6 4 x = v илиx = log ( v ) log ( 64 ) x = \frac{\log{\left(v \right)}}{\log{\left(64 \right)}} x = log ( 64 ) log ( v ) Тогда, окончательный ответx 1 = log ( 8 ) log ( 64 ) = 1 2 x_{1} = \frac{\log{\left(8 \right)}}{\log{\left(64 \right)}} = \frac{1}{2} x 1 = log ( 64 ) log ( 8 ) = 2 1
График
-12.5 -10.0 -7.5 -5.0 -2.5 0.0 2.5 5.0 7.5 10.0 12.5 15.0 0 10000000000000000000
x 1 = 1 2 x_{1} = \frac{1}{2} x 1 = 2 1 log(8) 2*pi*I
x2 = -------- - --------
6*log(2) 3*log(2) x 2 = log ( 8 ) 6 log ( 2 ) − 2 i π 3 log ( 2 ) x_{2} = \frac{\log{\left(8 \right)}}{6 \log{\left(2 \right)}} - \frac{2 i \pi}{3 \log{\left(2 \right)}} x 2 = 6 log ( 2 ) log ( 8 ) − 3 log ( 2 ) 2 iπ log(8) pi*I
x3 = -------- - --------
6*log(2) 3*log(2) x 3 = log ( 8 ) 6 log ( 2 ) − i π 3 log ( 2 ) x_{3} = \frac{\log{\left(8 \right)}}{6 \log{\left(2 \right)}} - \frac{i \pi}{3 \log{\left(2 \right)}} x 3 = 6 log ( 2 ) log ( 8 ) − 3 log ( 2 ) iπ log(8) pi*I
x4 = -------- + --------
6*log(2) 3*log(2) x 4 = log ( 8 ) 6 log ( 2 ) + i π 3 log ( 2 ) x_{4} = \frac{\log{\left(8 \right)}}{6 \log{\left(2 \right)}} + \frac{i \pi}{3 \log{\left(2 \right)}} x 4 = 6 log ( 2 ) log ( 8 ) + 3 log ( 2 ) iπ log(8) 2*pi*I
x5 = -------- + --------
6*log(2) 3*log(2) x 5 = log ( 8 ) 6 log ( 2 ) + 2 i π 3 log ( 2 ) x_{5} = \frac{\log{\left(8 \right)}}{6 \log{\left(2 \right)}} + \frac{2 i \pi}{3 \log{\left(2 \right)}} x 5 = 6 log ( 2 ) log ( 8 ) + 3 log ( 2 ) 2 iπ 1 pi*I
x6 = - + ------
2 log(2) x 6 = 1 2 + i π log ( 2 ) x_{6} = \frac{1}{2} + \frac{i \pi}{\log{\left(2 \right)}} x 6 = 2 1 + log ( 2 ) iπ
Сумма и произведение корней
[src] log(8) 2*pi*I log(8) pi*I log(8) pi*I log(8) 2*pi*I 1 pi*I
0 + 1/2 + -------- - -------- + -------- - -------- + -------- + -------- + -------- + -------- + - + ------
6*log(2) 3*log(2) 6*log(2) 3*log(2) 6*log(2) 3*log(2) 6*log(2) 3*log(2) 2 log(2) ( ( ( ( ( 0 + 1 2 ) + ( log ( 8 ) 6 log ( 2 ) − 2 i π 3 log ( 2 ) ) ) + ( log ( 8 ) 6 log ( 2 ) − i π 3 log ( 2 ) ) ) + ( log ( 8 ) 6 log ( 2 ) + i π 3 log ( 2 ) ) ) + ( log ( 8 ) 6 log ( 2 ) + 2 i π 3 log ( 2 ) ) ) + ( 1 2 + i π log ( 2 ) ) \left(\left(\left(\left(\left(0 + \frac{1}{2}\right) + \left(\frac{\log{\left(8 \right)}}{6 \log{\left(2 \right)}} - \frac{2 i \pi}{3 \log{\left(2 \right)}}\right)\right) + \left(\frac{\log{\left(8 \right)}}{6 \log{\left(2 \right)}} - \frac{i \pi}{3 \log{\left(2 \right)}}\right)\right) + \left(\frac{\log{\left(8 \right)}}{6 \log{\left(2 \right)}} + \frac{i \pi}{3 \log{\left(2 \right)}}\right)\right) + \left(\frac{\log{\left(8 \right)}}{6 \log{\left(2 \right)}} + \frac{2 i \pi}{3 \log{\left(2 \right)}}\right)\right) + \left(\frac{1}{2} + \frac{i \pi}{\log{\left(2 \right)}}\right) ( ( ( ( ( 0 + 2 1 ) + ( 6 log ( 2 ) log ( 8 ) − 3 log ( 2 ) 2 iπ ) ) + ( 6 log ( 2 ) log ( 8 ) − 3 log ( 2 ) iπ ) ) + ( 6 log ( 2 ) log ( 8 ) + 3 log ( 2 ) iπ ) ) + ( 6 log ( 2 ) log ( 8 ) + 3 log ( 2 ) 2 iπ ) ) + ( 2 1 + log ( 2 ) iπ ) 2*log(8) pi*I
1 + -------- + ------
3*log(2) log(2) 1 + 2 log ( 8 ) 3 log ( 2 ) + i π log ( 2 ) 1 + \frac{2 \log{\left(8 \right)}}{3 \log{\left(2 \right)}} + \frac{i \pi}{\log{\left(2 \right)}} 1 + 3 log ( 2 ) 2 log ( 8 ) + log ( 2 ) iπ / log(8) 2*pi*I \ / log(8) pi*I \ / log(8) pi*I \ / log(8) 2*pi*I \ /1 pi*I \
1*1/2*|-------- - --------|*|-------- - --------|*|-------- + --------|*|-------- + --------|*|- + ------|
\6*log(2) 3*log(2)/ \6*log(2) 3*log(2)/ \6*log(2) 3*log(2)/ \6*log(2) 3*log(2)/ \2 log(2)/ 1 ⋅ 1 2 ( log ( 8 ) 6 log ( 2 ) − 2 i π 3 log ( 2 ) ) ( log ( 8 ) 6 log ( 2 ) − i π 3 log ( 2 ) ) ( log ( 8 ) 6 log ( 2 ) + i π 3 log ( 2 ) ) ( log ( 8 ) 6 log ( 2 ) + 2 i π 3 log ( 2 ) ) ( 1 2 + i π log ( 2 ) ) 1 \cdot \frac{1}{2} \left(\frac{\log{\left(8 \right)}}{6 \log{\left(2 \right)}} - \frac{2 i \pi}{3 \log{\left(2 \right)}}\right) \left(\frac{\log{\left(8 \right)}}{6 \log{\left(2 \right)}} - \frac{i \pi}{3 \log{\left(2 \right)}}\right) \left(\frac{\log{\left(8 \right)}}{6 \log{\left(2 \right)}} + \frac{i \pi}{3 \log{\left(2 \right)}}\right) \left(\frac{\log{\left(8 \right)}}{6 \log{\left(2 \right)}} + \frac{2 i \pi}{3 \log{\left(2 \right)}}\right) \left(\frac{1}{2} + \frac{i \pi}{\log{\left(2 \right)}}\right) 1 ⋅ 2 1 ( 6 log ( 2 ) log ( 8 ) − 3 log ( 2 ) 2 iπ ) ( 6 log ( 2 ) log ( 8 ) − 3 log ( 2 ) iπ ) ( 6 log ( 2 ) log ( 8 ) + 3 log ( 2 ) iπ ) ( 6 log ( 2 ) log ( 8 ) + 3 log ( 2 ) 2 iπ ) ( 2 1 + log ( 2 ) iπ ) (-4*pi*I + log(8))*(-2*pi*I + log(8))*(2*pi*I + log(2))*(2*pi*I + log(8))*(4*pi*I + log(8))
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5
5184*log (2) ( log ( 2 ) + 2 i π ) ( log ( 8 ) − 4 i π ) ( log ( 8 ) − 2 i π ) ( log ( 8 ) + 2 i π ) ( log ( 8 ) + 4 i π ) 5184 log ( 2 ) 5 \frac{\left(\log{\left(2 \right)} + 2 i \pi\right) \left(\log{\left(8 \right)} - 4 i \pi\right) \left(\log{\left(8 \right)} - 2 i \pi\right) \left(\log{\left(8 \right)} + 2 i \pi\right) \left(\log{\left(8 \right)} + 4 i \pi\right)}{5184 \log{\left(2 \right)}^{5}} 5184 log ( 2 ) 5 ( log ( 2 ) + 2 iπ ) ( log ( 8 ) − 4 iπ ) ( log ( 8 ) − 2 iπ ) ( log ( 8 ) + 2 iπ ) ( log ( 8 ) + 4 iπ ) x2 = 0.5 - 3.0215734278848*i x3 = 0.5 - 1.5107867139424*i x4 = 0.5 + 1.5107867139424*i x5 = 0.5 + 3.0215734278848*i x6 = 0.5 + 4.53236014182719*i