Найду корень уравнения: х²-6х-280=0
2 x - 6*x - 280 = 0
a*x^2 + b*x + c = 0
D = b^2 - 4 * a * c =
(-6)^2 - 4 * (1) * (-280) = 1156
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
x1 = -14
x2 = 20
x1 = -14.0
x2 = 20.0