x-1=1+y/2
-1 = (y + 1)/2
-1 = y/2 + 1
i - 1 = (y + 1)/2
i - 1 = y/2 + 1
n - 1 = (y + 1)/2
n - 1 = y/2 + 1
x + 1 = (y + 1)/2
x + 1 = y/2 + 1
x = (y + 1)/2
x = y/2 + 1
x - 12 = (y + 1)/2
x - 12 = y/2 + 1
x - 1 = (y + 1)/2
x - 1 = y/2 + 1
Найду корень уравнения: x-1=1+y/2
y x - 1 = 1 + - 2
x-1 = 1+y/2
x = 2 / ((x - y/2)/x)
re(y) I*im(y) x1 = 2 + ----- + ------- 2 2