Найду корень уравнения: Х^2+2х-3=0
2 x + 2*x - 3 = 0
a*x^2 + b*x + c = 0
D = b^2 - 4 * a * c =
(2)^2 - 4 * (1) * (-3) = 16
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
x1 = -3
x2 = 1
x1 = 1.0
x2 = -3.0