Найду корень уравнения: x^2+3x=0
2 x + 3*x = 0
a*x^2 + b*x + c = 0
D = b^2 - 4 * a * c =
(3)^2 - 4 * (1) * (0) = 9
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
x1 = -3
x2 = 0
x1 = -3.0
x2 = 0.0