Интеграл cos(x^2-1) (dx)

Вы ввели

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 |  cos\x  - 1/ dx
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$$\int_{0}^{1} \cos{\left (x^{2} - 1 \right )}\, dx$$

Ответ

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$${{\sqrt{\pi}\,\left(\left(\left(\sqrt{2}\,i+\sqrt{2}\right)\,\sin 1 +\left(\sqrt{2}-\sqrt{2}\,i\right)\,\cos 1\right)\,\mathrm{erf} \left({{\sqrt{2}\,i+\sqrt{2}}\over{2}}\right)+\left(\left(\sqrt{2}\, i-\sqrt{2}\right)\,\sin 1+\left(-\sqrt{2}\,i-\sqrt{2}\right)\,\cos 1 \right)\,\mathrm{erf}\left({{\sqrt{2}\,i-\sqrt{2}}\over{2}}\right)+ \left(\left(\sqrt{2}-\sqrt{2}\,i\right)\,\sin 1+\left(\sqrt{2}\,i+ \sqrt{2}\right)\,\cos 1\right)\,\mathrm{erf}\left(\sqrt{-i}\right)+ \left(\left(\sqrt{2}\,i+\sqrt{2}\right)\,\sin 1+\left(\sqrt{2}- \sqrt{2}\,i\right)\,\cos 1\right)\,\mathrm{erf}\left(\left(-1\right) ^{{{1}\over{4}}}\right)\right)}\over{16}}$$

Численный ответ

0.749798304856986

Ответ (Неопределённый)

$${{\sqrt{\pi}\,\left(\left(\left(\sqrt{2}\,i+\sqrt{2}\right)\,\sin 1 +\left(\sqrt{2}-\sqrt{2}\,i\right)\,\cos 1\right)\,\mathrm{erf} \left({{\left(\sqrt{2}\,i+\sqrt{2}\right)\,x}\over{2}}\right)+\left( \left(\sqrt{2}\,i-\sqrt{2}\right)\,\sin 1+\left(-\sqrt{2}\,i-\sqrt{2 }\right)\,\cos 1\right)\,\mathrm{erf}\left({{\left(\sqrt{2}\,i- \sqrt{2}\right)\,x}\over{2}}\right)+\left(\left(\sqrt{2}-\sqrt{2}\,i \right)\,\sin 1+\left(\sqrt{2}\,i+\sqrt{2}\right)\,\cos 1\right)\, \mathrm{erf}\left(\sqrt{-i}\,x\right)+\left(\left(\sqrt{2}\,i+\sqrt{ 2}\right)\,\sin 1+\left(\sqrt{2}-\sqrt{2}\,i\right)\,\cos 1\right)\, \mathrm{erf}\left(\left(-1\right)^{{{1}\over{4}}}\,x\right)\right) }\over{16}}$$