1
/
| log(1 - sin(1)) log(1 + sin(1))
| -tan(x)*sin(x) dx = --------------- - --------------- + sin(1)
| 2 2
/
0
$$-{{\log \left(\sin 1+1\right)}\over{2}}+{{\log \left(1-\sin 1
\right)}\over{2}}+\sin 1$$
Ответ (Неопределённый)
[src] /
| log(-1 + sin(x)) log(1 + sin(x))
| -tan(x)*sin(x) dx = C + ---------------- - --------------- + sin(x)
| 2 2
/
$$-{{\log \left(\sin x+1\right)}\over{2}}+{{\log \left(\sin x-1
\right)}\over{2}}+\sin x$$