1 1
/ /
| |
| 1 | 1
| ---------- dx = | ---------- dx
| log(x) + 1 | 1 + log(x)
| |
/ /
0 0
$$\int_{0}^{1} \frac{1}{\log{\left (x \right )} + 1}\, dx = \int_{0}^{1} \frac{1}{\log{\left (x \right )} + 1}\, dx$$
Ответ (Неопределённый)
[src] / /
| |
| 1 | 1
| ---------- dx = C + | ---------- dx
| log(x) + 1 | 1 + log(x)
| |
/ /
$$-e^ {- 1 }\,{\it expintegral\_e}\left(1 , -\log x-1\right)$$