1
/
| 2
| -x 1 - log (5) - log(5)
| x*5 dx = ------- + ------------------
| 2 3
/ log (5) 5*log (5)
0
$${{1}\over{\left(\log 5\right)^2}}-{{\log 5+1}\over{5\,\left(\log 5
\right)^2}}$$
Ответ (Неопределённый)
[src] /
| -x / 2 \
| -x 5 *\-log(5) - x*log (5)/
| x*5 dx = C + -------------------------
| 3
/ log (5)
$$-{{\left(\log 5\,x+1\right)\,e^ {- \log 5\,x }}\over{\left(\log 5
\right)^2}}$$