x a
d / x\ --\a / dx
∂∂xax=axlog(a)\frac{\partial}{\partial x} a^{x} = a^{x} \log{\left(a \right)}∂x∂ax=axlog(a)
Ответ:
axlog(a)a^{x} \log{\left(a \right)}axlog(a)
x a *log(a)
x 2 a *log (a)
x 3 a *log (a)