2
--------------
2
1 + (2*x + 1)
$$\frac{2}{\left(2 x + 1\right)^{2} + 1}$$
-8*(1 + 2*x)
-----------------
2
/ 2\
\1 + (1 + 2*x) /
$$- \frac{16 x + 8}{\left(\left(2 x + 1\right)^{2} + 1\right)^{2}}$$
/ 2 \
| 4*(1 + 2*x) |
16*|-1 + --------------|
| 2|
\ 1 + (1 + 2*x) /
------------------------
2
/ 2\
\1 + (1 + 2*x) /
$$\frac{\frac{64 \left(2 x + 1\right)^{2}}{\left(2 x + 1\right)^{2} + 1} - 16}{\left(\left(2 x + 1\right)^{2} + 1\right)^{2}}$$